document.write( "Question 298080: put the following equation in standard form, identify center and radius and graph. x squared + y squared+ 6x-4y+12=0 \n" ); document.write( "
Algebra.Com's Answer #214862 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! x^2 + y^2+ 6x-4y+12=0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2+6x+9-9 + y^2-4y+4-4+12=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+3)^2-9 + (y-2)^2-4+12=0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+3)^2+(y-2)^2=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Circle with center (-3,2) and radius 1 \n" ); document.write( " |