document.write( "Question 298725: \r
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document.write( "Find the equations for the following lines and then graph them using any graphing utility \r
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document.write( "Parallel to 6x - 4y + 12 = 0, and passing through the line x = 3\r
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document.write( "6 times (3)-4y+12=0
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document.write( "18-4y+12=0 y=30/4 or 7.5
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document.write( "30-4y=0
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document.write( "30=4y
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document.write( "6x-4y+12=0 -4y/-4 = 6x+12/-4
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document.write( "4y=6x+12 y=6/-4x + 12 y=1.5x+12\r
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document.write( "slope = 6/-4 solution (3, 7.5)\r
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document.write( "So I was able to get this much not sure if it is correct however I am lost when it comes to the graphing and the part of the problem whre it states passing through the line x=3\r
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document.write( "any help is much appreciated and needed Thank you\r
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document.write( "Eric \n" );
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Algebra.Com's Answer #214800 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Please don't yell. We can hear you. We have new batteries in the hearing aids. \n" ); document.write( "HELLO I AM LOST ON THIS PROBLEMI I WAS ABLE TO COME UP WITH PART OF THE ANSWER BUT I AM NOW STUCK. I ALSO HAVE NO CLUE HOW TO GRAPH THIS ANY HELP WOULD BE APPRECIATED.\r \n" ); document.write( "\n" ); document.write( "All Caps is internet yelling.\r \n" ); document.write( "\n" ); document.write( "If it passes through x=3 that means the new line at some time has x=3 \n" ); document.write( "the original line has the equation 6x - 4y + 12 = 0 \n" ); document.write( "it has a slope of -a/b=-6/-4=3/2 \n" ); document.write( "The new line will also have a slope of 3/2 \n" ); document.write( " and an x of 3\r \n" ); document.write( "\n" ); document.write( "y=3x/2 is our new line \n" ); document.write( "We are pretty sure it will pass through x=3 \n" ); document.write( "But how can we be sure? \n" ); document.write( "The only lines that won't pass through x=3 are parallel with x=3 x=3 has an undefined slope since y never changes. \n" ); document.write( "Our line has a slope of 3/2 so they do intersect. \n" ); document.write( "As a further test we can see if the original line passes through x=3 \n" ); document.write( "by plugging in 3 for x in the original equation but it is not necessary. \n" ); document.write( " \n" ); document.write( " |