document.write( "Question 298582: A train leaves Watsonville at noon traveling north at 44 mph. One hour later, another train, going 52 mph, travels north on a parallel track. How many hours will the second train travel before it overtakes the first train? Show your work. PLEASE EXP[LAIN IT STEP BY STEP \n" ); document.write( "
Algebra.Com's Answer #214797 by ankor@dixie-net.com(22740)\"\" \"About 
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A train leaves Watsonville at noon traveling north at 44 mph.
\n" ); document.write( " One hour later, another train, going 52 mph, travels north on a parallel track.
\n" ); document.write( " How many hours will the second train travel before it overtakes the first train?
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\n" ); document.write( "Let t = travel time of the 2nd train
\n" ); document.write( "The 1st train left 1 hr earlier, therefore
\n" ); document.write( "(t+1) = travel time of the 1st train
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\n" ); document.write( "When the 2nd train overtakes the 1st, they will have traveled the same distance
\n" ); document.write( "Write a distance equation from this fact; Dist = speed * time
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\n" ); document.write( "2nd train dist = 1st train dist
\n" ); document.write( "52t = 44(t+1)
\n" ); document.write( "52t = 44t + 44; multiplied whats inside the brackets
\n" ); document.write( "52t - 44t - 44; subtracted 44t from both sides
\n" ); document.write( "8t = 44
\n" ); document.write( "t = \"44%2F8\"; divide both sides by 8
\n" ); document.write( "t = 5.5 hrs travel time of the 2nd train
\n" ); document.write( "and
\n" ); document.write( "5.5 + 1 = 6.5 hr travel time of the 1st train
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\n" ); document.write( "Check this by finding the distance of each train
\n" ); document.write( "52 * 5.5 = 286 mi, 2nd train dist
\n" ); document.write( "44 * 6.5 = 286 mi also, confirms our solution
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\n" ); document.write( "Was this step-by-step enough for you to clearly understand this?
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