document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=298701>Question 298701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twenty four is divided into two parts such that 7 times the first part added to 5 times the second part makes 146. Find each part. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #214782 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=214782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> twenty four is divided into two parts such that 7 times the first part added to 5 times the second part makes 146. Find each part.\r<BR>\n" );
document.write( "\n" );
document.write( "let one part be x.----------- 7 times the first part = 7x\r<BR>\n" );
document.write( "\n" );
document.write( "the other part will be 24-x.---- 5 times the secon part = 5 ( 24-x)\r<BR>\n" );
document.write( "\n" );
document.write( "7x+5(24-x)=146\r<BR>\n" );
document.write( "\n" );
document.write( "7x+120-5x=146\r<BR>\n" );
document.write( "\n" );
document.write( "2x=146-120<BR>\n" );
document.write( "2x=26<BR>\n" );
document.write( "x=13\r<BR>\n" );
document.write( "\n" );
document.write( "other part is 11 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );