document.write( "Question 298681: three times a first number decreased by a second number is one. the first number increased by twice the second number is 12. find the numbers \n" ); document.write( "

Algebra.Com's Answer #214775 by mananth(16946) $\"\"$ $\"About$

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three times a first number decreased by a second number is one. the first number increased by twice the second number is 12. find the numbers\r
\n" ); document.write( "\n" ); document.write( "let one number be x
\n" ); document.write( "& the other number be y\r
\n" ); document.write( "\n" ); document.write( "3x-y=1\r
\n" ); document.write( "\n" ); document.write( "x+2y=12 Multiply by 3 and subtract from above equation\r
\n" ); document.write( "\n" ); document.write( "3x-y -3(x+2y)=1 -3*12\r
\n" ); document.write( "\n" ); document.write( "3x-y-3x-6y=-35\r
\n" ); document.write( "\n" ); document.write( "-7y=-35
\n" ); document.write( "y=-35/-7\r
\n" ); document.write( "\n" ); document.write( "y=5\r
\n" ); document.write( "\n" ); document.write( "3x-y=1\r
\n" ); document.write( "\n" ); document.write( "3x-5=1\r
\n" ); document.write( "\n" ); document.write( "3x=6
\n" ); document.write( "x=6/2\r
\n" ); document.write( "\n" ); document.write( "x=2\r
\n" ); document.write( "\n" ); document.write( "x=2 y=5\r
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