document.write( "Question 298625: I need to solve this by losing the fraction\r
\n" );
document.write( "\n" );
document.write( "2n-3 over 2 = 3/4 \n" );
document.write( "
Algebra.Com's Answer #214757 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2n-3 / 2= 3/4\r \n" ); document.write( "\n" ); document.write( "eliminate the denominator on the left hand side of the equation by multiplying by 2\r \n" ); document.write( "\n" ); document.write( "2n-3 / 2 * 2 = 3/4 * 2\r \n" ); document.write( "\n" ); document.write( "2n-3 = 3/2\r \n" ); document.write( "\n" ); document.write( "similarly for right hand side of the equation multiply by 2\r \n" ); document.write( "\n" ); document.write( "2(2n-3) = 3/2 * 2\r \n" ); document.write( "\n" ); document.write( "4n-6=3\r \n" ); document.write( "\n" ); document.write( "4n=6+3\r \n" ); document.write( "\n" ); document.write( "4n=9\r \n" ); document.write( "\n" ); document.write( "n=9/4 \r \n" ); document.write( "\n" ); document.write( "---------------\r \n" ); document.write( "\n" ); document.write( "2n-3 / 2= 3/4\r \n" ); document.write( "\n" ); document.write( "OR later you could just do it this way\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4(2n-3) = 2*3\r \n" ); document.write( "\n" ); document.write( "8n-12 = 6\r \n" ); document.write( "\n" ); document.write( "8n=6+12\r \n" ); document.write( "\n" ); document.write( "8n=18\r \n" ); document.write( "\n" ); document.write( "n=18/8\r \n" ); document.write( "\n" ); document.write( "n= 9/4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |