document.write( "Question 298487: A man travels from Town X to Town Y at an average rate of 60 mph and returns at an average rate of 50 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 55 mph. What is the distance from Town X to Town Y? \n" ); document.write( "
Algebra.Com's Answer #214697 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A man travels from Town X to Town Y at an average rate of 60 mph and returns at an average rate of 50 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 55 mph. What is the distance from Town X to Town Y? \n" ); document.write( "--------- \n" ); document.write( "To-trip DATA: \n" ); document.write( "distance = d miles ; rate = 60 mph ; time = d/60 hrs \n" ); document.write( "---------------------- \n" ); document.write( "From-trip DATA: \n" ); document.write( "distance = d miles ; rate = 50 mph ; time = d/50 hrs \n" ); document.write( "---------------------- \n" ); document.write( "Round-trip DATA: \n" ); document.write( "distance = 2d miles ; rate = 55 mph ; time = (2d)/55 hrs \n" ); document.write( "----------------------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "Roundtrip time - other time = -1/2 hr \n" ); document.write( "(2d)/55 - [(d/60)+(d/50)] = -1/2 \n" ); document.write( "(2d)/55 - [(110d)/(50*60)] = -1/2 \n" ); document.write( "--- \n" ); document.write( "600(2d) - 11[110d] = -16500 \n" ); document.write( "1200d - 1210d = -16500 \n" ); document.write( "-10d = -16500 \n" ); document.write( "distance = 1650 miles \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========================== \n" ); document.write( " \n" ); document.write( " |