document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=298485>Question 298485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photograph 8 cm by 11 cm will be framed as shown in the diagram. The <BR>\n" );
document.write( "      combined area of the frame and photograph will be 180 cm2. Algebraically<BR>\n" );
document.write( "      determine the outside dimensions of the frame.<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #214687 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=214687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (8+2X)(11+2X)=180<BR>\n" );
document.write( "88+38X+4X^2=180<BR>\n" );
document.write( "4X62+38X+88-180=0<BR>\n" );
document.write( "4X^2+38X-92=0<BR>\n" );
document.write( "(2X-4)(2X+23)=0<BR>\n" );
document.write( "2X-4=0<BR>\n" );
document.write( "2X=4<BR>\n" );
document.write( "X=4/2<BR>\n" );
document.write( "X=2 cm is the width of the frame.<BR>\n" );
document.write( "The dimentios odf the picture & frame is:<BR>\n" );
document.write( "8+4=12<BR>\n" );
document.write( "11+4=15<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "12*15=180<BR>\n" );
document.write( "180=180<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );