document.write( "Question 298305: Can you help me solve this word problem?\r
\n" ); document.write( "\n" ); document.write( "Two pipes can fill a large tank in 10 hours. One of the pipes, used alone, takes 15 hours longer than the other to fill the tank. How long would each pipe take to fill the tank alone?
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Algebra.Com's Answer #214667 by ankor@dixie-net.com(22740)\"\" \"About 
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Two pipes can fill a large tank in 10 hours. One of the pipes, used alone,
\n" ); document.write( " takes 15 hours longer than the other to fill the tank.
\n" ); document.write( " How long would each pipe take to fill the tank alone?
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\n" ); document.write( "\n" ); document.write( "Let x = time for one of the pipes to fill the tank alone
\n" ); document.write( "then
\n" ); document.write( "(x+15) = time for the other pipe to do it
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\n" ); document.write( "Let the completed job = 1 (a full tank)
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\n" ); document.write( "A typical shared work equation
\n" ); document.write( "\"10%2Fx\" + \"10%2F%28%28x%2B15%29%29\" = 1
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\n" ); document.write( "Multiply equation by x(x+15), results:
\n" ); document.write( "10(x+15) + 10x = x(x+15)
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\n" ); document.write( "10x + 150 + 10x = x^2 + 15x
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\n" ); document.write( "Arrange as a quadratic equation on the right
\n" ); document.write( "0 = x^2 + 15x - 20x - 150
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\n" ); document.write( "x^2 - 5x - 150 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-15)(x+10) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "x = 15 hrs is one pipe
\n" ); document.write( "and
\n" ); document.write( "15 + 15 = 30 hrs is the other pipe
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\n" ); document.write( "Check solution in the original shared work equation
\n" ); document.write( "\"10%2F15\" + \"10%2F30\" = 1
\n" ); document.write( ".667 + .333 = 1.0
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