document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=298345>Question 298345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much soil containing 45% sand do you need to add to 1 ft3 of soil containing 15% sand in order to make a soil containing 35%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #214649 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=214649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much soil containing 45% sand do you need to add to 1 ft3 of soil containing 15% sand in order to make a soil containing 35%?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "sand + sand = sand<BR>\n" );
document.write( "0.45x + 0.15*1 = 0.35(x+1)<BR>\n" );
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document.write( "Multiply thru by 100:<BR>\n" );
document.write( "45x + 15 = 35x + 35<BR>\n" );
document.write( "10x = 10<BR>\n" );
document.write( "x = 1 ft^3 (amount of 45% soil needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );