document.write( "Question 35350: Question goes like this....\r
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document.write( "Solve Equation.\r
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document.write( "log x + log (x+2) = log 3 \n" );
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Algebra.Com's Answer #21462 by narayaba(40)![]() ![]() ![]() You can put this solution on YOUR website! log x + log (x+2) = log 3 \n" ); document.write( "log(a) + log(b) = log(a*b) \n" ); document.write( "log(x) + log(x+2) = log(x*(x+2)) = log3 \n" ); document.write( "log(x*(x+2)) = log3 \n" ); document.write( "log on the right and left are of the same base \n" ); document.write( "therefore x(x+2) = 3 \n" ); document.write( "x^2 +2x -3 = 0 factorising \n" ); document.write( "(x+3)(x-1) = 0 \n" ); document.write( "x=-3 or x = 1\r \n" ); document.write( "\n" ); document.write( "log of negative number is not possible hence x =1 \n" ); document.write( " |