document.write( "Question 298182: The base of a triangle is 7 cm longer than its altitude. The area of the triangle is
\n" ); document.write( "30 cm2. Find the length of the altitude. \n" ); document.write( "
Algebra.Com's Answer #214569 by nerdybill(7384)\"\" \"About 
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The base of a triangle is 7 cm longer than its altitude. The area of the triangle is 30 cm2. Find the length of the altitude.
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\n" ); document.write( "Area of any triangle is:
\n" ); document.write( "area = (1/2)bh
\n" ); document.write( "where
\n" ); document.write( "b is base
\n" ); document.write( "h is height or altitude
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\n" ); document.write( "Let x = altitude
\n" ); document.write( "then
\n" ); document.write( "x+7 = base
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\n" ); document.write( "plugging in what is given into:
\n" ); document.write( "area = (1/2)bh
\n" ); document.write( "30 = (1/2)(x+7)x
\n" ); document.write( "60 = (x+7)x
\n" ); document.write( "60 = x^2+7x
\n" ); document.write( "0 = x^2+7x-60
\n" ); document.write( "0 = (x+12)(x-5)
\n" ); document.write( "x = 5 cm\r
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