document.write( "Question 298175: x+1+sqrt(x+4)=9
\n" ); document.write( "once I isolate the radical I end up with x+4=(8-X)(8-x) WHat do I do next.
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Algebra.Com's Answer #214568 by MathTherapy(10858)\"\" \"About 
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x+1+sqrt(x+4)=9
\n" ); document.write( "once I isolate the radical I end up with x+4=(8-X)(8-x) WHat do I do next.\r
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\n" ); document.write( "\n" ); document.write( "\"x+%2B+1+%2B+sqrt%28x+%2B+4%29+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x+%2B+4%29+=+8+-+x\"\r
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\n" ); document.write( "\n" ); document.write( "x + 4 = (8 - x)(8 - x)------- Square both sides of equation\r
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\n" ); document.write( "\n" ); document.write( "\"x+%2B+4+=+64+-+16x+%2B+x%5E2\" ------ FOILing right-side of equation\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+x%5E2+-+17x+%2B+60\" -------> \"x%5E2+-+17x+%2B+60+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "(x - 12)(x - 5) = 0\r
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\n" ); document.write( "\n" ); document.write( "x = 12 or 5\r
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\n" ); document.write( "\n" ); document.write( "However, when 12 is substituted back into the original equation, we get: \r
\n" ); document.write( "\n" ); document.write( "\"12+%2B+1+%2B+sqrt%2812%2B4%29+=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"13+%2B+sqrt%2816%29+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"13+%2B+4+%3C%3E+9\"\r
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\n" ); document.write( "\n" ); document.write( "But, when 5 is substituted back into the original equation, we get: \r
\n" ); document.write( "\n" ); document.write( "\"5+%2B+1+%2B+sqrt%285%2B4%29+=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"6+%2B+sqrt%289%29+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"6+%2B+3+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the only solution is \"highlight_green%28x+=+5%29\"
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