document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35336>Question 35336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x+y=0<BR>\n" );
document.write( "-3x+y=-6\r<BR>\n" );
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document.write( "please help i'm very confusted as how to do this type of problem\r<BR>\n" );
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document.write( "thanks<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21454 by </B><A HREF=/tutors/aboutme.mpl?userid=narayaba><B>narayaba(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=narayaba><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + y = 0  equation 1<BR>\n" );
document.write( "-3x  + y = -6 equation 2<BR>\n" );
document.write( "from equation 1 we get y = -3x<BR>\n" );
document.write( "plugging in for -3x in equation 2<BR>\n" );
document.write( "y + y =-6<BR>\n" );
document.write( "2y =-6<BR>\n" );
document.write( "y = -3<BR>\n" );
document.write( "-3x = y<BR>\n" );
document.write( "-3x =-3<BR>\n" );
document.write( "x =1<BR>\n" );
document.write( "x= 1 and y =-3 </SPAN>\n" );
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