document.write( "Question 214449: 1. find the slope of the line that passes through the points (-2,3) and (5,-8).\r
\n" ); document.write( "\n" ); document.write( "2. find the equation of the line that passes through the points (3,-2)and(4,-2).\r
\n" ); document.write( "\n" ); document.write( "3. Find the equation, in standard form, with all interger coefficients, of the line perpendicular to x+ 3y=6 and passing through (-3,5). \n" ); document.write( "
Algebra.Com's Answer #214497 by alanc(27)\"\" \"About 
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1.) We want to find the slope of a line intersecting points (-2, 3) and (5,-8) use the definition of slope. SLOPE = (Y2 - Y1)/(X2 -X1) for points (X1, Y1) AND (X2, Y2). (note the significance of parentheses )\r
\n" ); document.write( "\n" ); document.write( "Here, SLOPE = (-8 - 3)/(5- (-2)) = -11/7\r
\n" ); document.write( "\n" ); document.write( "2.) An equation of a line through (3,-2), (4, -2) follows from previous solver: y=-2 because the line is horizontal.\r
\n" ); document.write( "\n" ); document.write( "3.) Standard form for a line is Ax + By = C for A and B not both zero.
\n" ); document.write( "first find the slope of x + 3y = 6, rearranging it to y = (-1/3)x + 2
\n" ); document.write( "Slope is (-1/3) for given line. The slope of a line perpendicular to this is 3, it is the negative reciprocal of (-1/3).\r
\n" ); document.write( "\n" ); document.write( "Next we have y - 5 = 3* (x - (-3))\r
\n" ); document.write( "\n" ); document.write( "y - 5 = 3x + 9\r
\n" ); document.write( "\n" ); document.write( "3x -y = -14\r
\n" ); document.write( "\n" ); document.write( "Answer: 3x -y = -14\r
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