document.write( "Question 35326: Problem goes like this...\r
\n" ); document.write( "\n" ); document.write( "Solve Equation.\r
\n" ); document.write( "\n" ); document.write( "log2 (5x+7) - log2 x = 2
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Algebra.Com's Answer #21448 by narayaba(40)\"\" \"About 
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log2 (5x+7) - log2 x = 2\r
\n" ); document.write( "\n" ); document.write( "log2(a) - log2(b) = log2 (a/b)\r
\n" ); document.write( "\n" ); document.write( "using the above identity
\n" ); document.write( "log2 ((5x+7)/x) = 2\r
\n" ); document.write( "\n" ); document.write( "log 2 to the base 2 is 1 i.e log2 2 = 1
\n" ); document.write( "2 can be written as 2*1 = 2log2 (2) = log2 (4)\r
\n" ); document.write( "\n" ); document.write( "log2 ((5x+7)/x) = log2 (4)\r
\n" ); document.write( "\n" ); document.write( "since the log on the right and the left side is with the same base
\n" ); document.write( "(5x + 7)/x = 4
\n" ); document.write( "5x + 7 = 4*x
\n" ); document.write( "x = -7
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