document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=297894>Question 297894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 36 meters and the length is 4 meters more than the width.\r<BR>\n" );
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document.write( "36= l(w+4)<BR>\n" );
document.write( "how would i get actual numbers out of this??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #214453 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=214453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 36= l(w+4) Wrong equation<BR>\n" );
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document.write( "L=W+4<BR>\n" );
document.write( "36=2L+2W iS THE PERIMETER FORMULA.<BR>\n" );
document.write( "36=2(W+4)+2W<BR>\n" );
document.write( "36=2W+8+2W<BR>\n" );
document.write( "36=4W+8<BR>\n" );
document.write( "4W=36-8<BR>\n" );
document.write( "4W=28<BR>\n" );
document.write( "W=28/4<BR>\n" );
document.write( "W=7 ans. for the width.<BR>\n" );
document.write( "L=7+4=11 ans. for the length.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "36=2*11+2*7<BR>\n" );
document.write( "36=22+14<BR>\n" );
document.write( "36=36  </SPAN>\n" );
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