document.write( "Question 297795: Solve for x\r
\n" ); document.write( "\n" ); document.write( "logx25=-0.5 ( the x is smaller than the log)
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Algebra.Com's Answer #214394 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%2C25%29+=+-+.5\"
\n" ); document.write( "This says that the base \"x\"
\n" ); document.write( "raised to the exponent \"-+.5\"
\n" ); document.write( "gives me \"25\", so I can write this as:
\n" ); document.write( "\"x%5E%28-1%2F2%29+=+25\"
\n" ); document.write( "\"1%2F%28x%5E%281%2F2%29%29+=+25\"
\n" ); document.write( "\"x%5E%281%2F2%29+=+1%2F25\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"x+=+1%2F625\"
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