document.write( "Question 35275This question is from textbook
\n" ); document.write( ": I don't understand this. It's frustrating. I was doing just fine In this chapter untill getting to this point. Can someone give me a step by step on how to do this? I have to graph the line with the given slope that goes through the given point. \r
\n" ); document.write( "\n" ); document.write( "In this problem it's: Through (0,-2) with m=1/2 \n" ); document.write( "
Algebra.Com's Answer #21438 by narayaba(40)\"\" \"About 
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The general equation of a straight line with slope m is y = m*x + c.
\n" ); document.write( "where c is the y intercept.\r
\n" ); document.write( "\n" ); document.write( "The slope of the line is given as 1/2\r
\n" ); document.write( "\n" ); document.write( "The equation of the line becomes y = 1/2*x + c (equation 1)
\n" ); document.write( "The only unknown in the above equation is c
\n" ); document.write( "To find out c\r
\n" ); document.write( "\n" ); document.write( "It is given that the line passes through (0,-2)\r
\n" ); document.write( "\n" ); document.write( "plugging in y = -2 and x = 0 in equation 1\r
\n" ); document.write( "\n" ); document.write( "we get -2 = 1/2 * 0 + c
\n" ); document.write( "-2 = 0 + c i.e c = -2
\n" ); document.write( "Thus the equation of the straight line is y = 1/2*x -2 \n" ); document.write( "
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