document.write( "Question 297725: Solve: log(x+2) + log(x-1) =1 \n" ); document.write( "
Algebra.Com's Answer #214376 by user_dude2008(1862)\"\" \"About 
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log(x+2) + log(x-1) =1\r
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\n" ); document.write( "\n" ); document.write( "log[(x+2)(x-1)] =1\r
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\n" ); document.write( "\n" ); document.write( "(x+2)(x-1)=10\r
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\n" ); document.write( "\n" ); document.write( "x^2+x-2=10\r
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\n" ); document.write( "\n" ); document.write( "x^2+x-12=0\r
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\n" ); document.write( "\n" ); document.write( "(x+4)(x-3)=0\r
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\n" ); document.write( "\n" ); document.write( "x+4=0 or x-3=0\r
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\n" ); document.write( "\n" ); document.write( "x=-4 or x=3\r
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\n" ); document.write( "\n" ); document.write( "Only answer is x=3
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