document.write( "Question 297644: Dr. Glendon, the school physician in charge of giving sports phyisicals, has compiled his information and has determined that the probability a student will be on a sports team is 0.39. yesterday. Dr. glendon examined five students chosen at random.\r
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document.write( "A)find to the nearest hundredth, the probability that at least 4 of the 5 students will be on a team.\r
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document.write( "B) find to the nearest hundredth, the probability that exactly one of the five students will not be on a team. \n" );
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Algebra.Com's Answer #214321 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Dr. Glendon, the school physician in charge of giving sports phyisicals, has compiled his information and has determined that the probability a student will be on a sports team is 0.39. yesterday. Dr. glendon examined five students chosen at random. \n" ); document.write( "P(willl be on) = 0.39 ; P(will not be on) = 0.61 \n" ); document.write( "------------------------------ \n" ); document.write( "A)find to the nearest hundredth, the probability that at least 4 of the 5 students will be on a team. \n" ); document.write( "P(4<= x <=5) = 1-P(0<= x <=3) = 1-binomcdf(5,0.39,3) = 0.0796 \n" ); document.write( "-------------------------------------- \n" ); document.write( "B) find to the nearest hundredth, the probability that exactly one of the five students will not be on a team. \n" ); document.write( "P(x = 1) = 5C1(0.61)*(0.39)^4 = binompdf(5,0.61,1) = 0.0706 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |