document.write( "Question 297656: Any help would be appreciated
\n" ); document.write( "Find the equations for the following lines and then graph them using any graphing utility
\n" ); document.write( "Parallel to 6x - 4y + 12 = 0, and passing through the line x = 3\r
\n" ); document.write( "\n" ); document.write( "John \n" ); document.write( "
Algebra.Com's Answer #214320 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
x=3 is a vertical line with slope undefined x is always 3 and y can be anything
\n" ); document.write( "If a line passes through x=3 that means x will be 3
\n" ); document.write( "So let's check that our line goes through x=3
\n" ); document.write( "6*3-4y+12=0
\n" ); document.write( "18-4y+12=0
\n" ); document.write( "30-4y=0
\n" ); document.write( "30=4y
\n" ); document.write( "30/4=y
\n" ); document.write( "Yes, it does pass through x=3
\n" ); document.write( "So a parallel line will also pass through x=3
\n" ); document.write( "So you need to find the slope of 6x-4y+12=0
\n" ); document.write( "where 6=a and b=-4 and -a/b is the slope
\n" ); document.write( "The new line will have the same slope.
\n" ); document.write( "Now you need to write an equation with that slope
\n" ); document.write( "y=mx where m is that slope.
\n" ); document.write( "done
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