document.write( "Question 297556: Juan can paint the neighbor's house four times as fast as Ariel. The year they worked together it took them 8 days. How long would it take each to paint the house alone? \n" ); document.write( "
Algebra.Com's Answer #214266 by MathTherapy(10559)\"\" \"About 
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Juan can paint the neighbor's house four times as fast as Ariel. The year they worked together it took them 8 days. How long would it take each to paint the house alone?\r
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\n" ); document.write( "\n" ); document.write( "Let the amount of days Juan takes to do the job be J\r
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\n" ); document.write( "\n" ); document.write( "Since Juan works 4 times faster than Ariel, then Ariel's time to do the entire job is 4J\r
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\n" ); document.write( "\n" ); document.write( "This means that Juan can do \"1%2FJ\" of the job in 1 day, and\r
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\n" ); document.write( "\n" ); document.write( "Ariel can do \"1%2F4J\" of the job in 1 day\r
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\n" ); document.write( "\n" ); document.write( "Now we get: \"8%2F%28J%29+%2B+8%2F%284J%29+=+1\" since it takes both men 8 days to do the entire job\r
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\n" ); document.write( "\n" ); document.write( "This gives us: 32 + 8 = 4J --------- Mutiplying by LCD, 4J\r
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\n" ); document.write( "\n" ); document.write( "40 = 4J\r
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\n" ); document.write( "\n" ); document.write( "Therefore, J, or Juan's time to do the job is: \"40%2F4\" or \"highlight_green%2810%29\" days, which means that Ariel can do the same job in 10*4 days, or \"highlight_green%2840%29\" days.
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