document.write( "Question 297556: Juan can paint the neighbor's house four times as fast as Ariel. The year they worked together it took them 8 days. How long would it take each to paint the house alone? \n" ); document.write( "
Algebra.Com's Answer #214266 by MathTherapy(10559) You can put this solution on YOUR website! Juan can paint the neighbor's house four times as fast as Ariel. The year they worked together it took them 8 days. How long would it take each to paint the house alone?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the amount of days Juan takes to do the job be J\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since Juan works 4 times faster than Ariel, then Ariel's time to do the entire job is 4J\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means that Juan can do \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ariel can do \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we get: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This gives us: 32 + 8 = 4J --------- Mutiplying by LCD, 4J\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "40 = 4J\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, J, or Juan's time to do the job is: |