document.write( "Question 297444: Hot chocolate sells for $.75 and coffee sells for $.50 at a football game. If they sold $200 worth of hot drinks and used 295 cups, how many of each drink did they sell? \n" ); document.write( "
Algebra.Com's Answer #214201 by josmiceli(19441)\"\" \"About 
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Let \"h\" = number of hot chocolates sold
\n" ); document.write( "Let \"c\" = number of coffees sold
\n" ); document.write( "given:
\n" ); document.write( "(1) \"h+%2B+c+=+295\"
\n" ); document.write( "(2) \".75h+%2B+.5c+=+200\"
\n" ); document.write( "Multiply both sides of (1) by \".5\"
\n" ); document.write( "and subtract from (2)
\n" ); document.write( "\".75h+%2B+.5c+=+200\"
\n" ); document.write( "\"-+.5h+-+.5c+=+-+147.5\"
\n" ); document.write( "\".25h+=+52.5\"
\n" ); document.write( "\"h+=+210\"
\n" ); document.write( "and, since
\n" ); document.write( "\"h+%2B+c+=+295\"
\n" ); document.write( "\"c+=+295+-+210\"
\n" ); document.write( "\"c+=+85\"
\n" ); document.write( "They sold 210 hot chocolates and 85 coffees
\n" ); document.write( "check:
\n" ); document.write( "(2) \".75h+%2B+.5c+=+200\"
\n" ); document.write( "(2) \".75%2A210+%2B+.5%2A85+=+200\"
\n" ); document.write( "\"157.5+%2B+42.5+=+200\"
\n" ); document.write( "\"200+=+200\"
\n" ); document.write( "OK\r
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