document.write( "Question 297402: Find two consecutive integers such that the square of the sum of the two integers is 11 more than the lesser integer.\r
\n" ); document.write( "\n" ); document.write( "I'm having a terrible time solving this. According to the book, the answer should be (-2,-1).I believe the formula is:
\n" ); document.write( "x = lesser #
\n" ); document.write( "x+1 = greater #\r
\n" ); document.write( "\n" ); document.write( "(x+x+1)^2=x+11\r
\n" ); document.write( "\n" ); document.write( "(2x+1)^2=x+11\r
\n" ); document.write( "\n" ); document.write( "4x^2+4x+2=x+11 (subtract the x+11 to bring it to the other side)\r
\n" ); document.write( "\n" ); document.write( "4x^2+3x-9=0 (this is also where I get stuck) \n" ); document.write( "

Algebra.Com's Answer #214187 by checkley77(12844) $\"\"$ $\"About$

You can put this solution on YOUR website!
(x+x+1)^2=x+11\r
\n" ); document.write( "\n" ); document.write( "(2x+1)^2=x+11\r
\n" ); document.write( "\n" ); document.write( "4x^2+4x+[1]=x+11 (subtract the x+11 to bring it to the other side)
\n" ); document.write( "[You missed the 1*1=1 term.]
\n" ); document.write( "4x^2+3x-[10]=0
\n" ); document.write( "(4x-5)(x+2)=0
\n" ); document.write( "4x-5=x=5/4 not an integer.
\n" ); document.write( "x+2=0
\n" ); document.write( "x=-2 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "(-2-1)^2=-2+11
\n" ); document.write( "-3^2=9
\n" ); document.write( "9=9 \n" ); document.write( "

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