document.write( "Question 297297: if AF = 2(x + 1)and AC = 5(x -2), find FC \n" ); document.write( "
Algebra.Com's Answer #214171 by checkley77(12844)\"\" \"About 
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AF=2(x+1)
\n" ); document.write( "F=2(X+1)/A
\n" ); document.write( "AC=5(x-2)
\n" ); document.write( "C=5(X-2)/A
\n" ); document.write( "FC=[2(X+1)/A][5(X-2)/A]
\n" ); document.write( "FC=[(2X+2)/A][(5X-10)/A]
\n" ); document.write( "FC=10X^2+10X-20X-20)/A^2
\n" ); document.write( "FC=(10X^2-10X-20)/A^2
\n" ); document.write( "FC=10(X^2-X-2)/A^2
\n" ); document.write( "FC=10(X-2)(X+1)/A^2
\n" ); document.write( "
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