document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=297386>Question 297386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the linear function:<BR>\n" );
document.write( "2x+3y=-9<BR>\n" );
document.write( "How do I get \"y\" by it's self? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #214164 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=214164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> get the 2x term on the right<BR>\n" );
document.write( "How ? subtract 2x from both sides<BR>\n" );
document.write( "now you have 3y=-2x-9<BR>\n" );
document.write( "now divide  by 3<BR>\n" );
document.write( "y=-2x/3-9/3<BR>\n" );
document.write( "y=-2x/3-3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );