document.write( "Question 35258This question is from textbook Beginning & Intermediate Algebra
\n" ); document.write( ": S=4lw + 2wh; s=102, l=7, w=3 \n" ); document.write( "
Algebra.Com's Answer #21415 by ichudov(507)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SUBSTITUTION solver -- compute expression given values
Your Result:

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  • This is an equation! Solutions: h=3.
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  • Graphical form: Equation \"s=4l%2Aw%2B2w%2Ah\" was fully solved.
  • Text form: s=4l*w+2w*h simplifies to 0=0
  • Cartoon (animation) form: \"simplify_cartoon%28+s=4l%2Aw%2B2w%2Ah+%29\"
    For tutors: simplify_cartoon( s=4l*w+2w*h )
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  • If you have a website, here's a link to this solution.
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DETAILED EXPLANATION

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Look at \"highlight_red%28+s+%29=4l%2Aw%2B2w%2Ah\".
Replaced s with 102
It becomes \"highlight_green%28+102+%29=4l%2Aw%2B2w%2Ah\".
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Look at \"102=4%2Ahighlight_red%28+l+%29%2Aw%2B2%2Aw%2Ah\".
Replaced l with 7
It becomes \"102=4%2Ahighlight_green%28+7+%29%2Aw%2B2%2Aw%2Ah\".
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Look at \"102=4%2A7%2Ahighlight_red%28+w+%29%2B2%2Aw%2Ah\".
Replaced w with 3
It becomes \"102=4%2A7%2Ahighlight_green%28+3+%29%2B2%2Aw%2Ah\".
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Look at \"102=4%2A7%2A3%2B2%2Ahighlight_red%28+w+%29%2Ah\".
Replaced w with 3
It becomes \"102=4%2A7%2A3%2B2%2Ahighlight_green%28+3+%29%2Ah\".
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Look at \"102=highlight_red%28+4%2A7%2A3+%29%2B2%2A3%2Ah\".
Moved \"4%2A7%2A3\" to the right of expression
It becomes \"102=2%2A3%2Ah%2Bhighlight_green%28+4%2A7%2A3+%29\".
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Look at \"102=highlight_red%28+2+%29%2Ahighlight_red%28+3+%29%2Ah%2B4%2A7%2A3\".
Multiplied numerator integers
It becomes \"102=highlight_green%28+6+%29%2Ah%2B4%2A7%2A3\".
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Look at \"102=6%2Ah%2Bhighlight_red%28+4+%29%2Ahighlight_red%28+7+%29%2Ahighlight_red%28+3+%29\".
Multiplied numerator integers
It becomes \"102=6%2Ah%2Bhighlight_green%28+84+%29\".
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Look at \"102=highlight_red%28+6%2Ah%2B84+%29\".
Moved these terms to the left \"highlight_green%28+-6%2Ah+%29\",\"highlight_green%28+-84+%29\"
It becomes \"102-highlight_green%28+6%2Ah+%29-highlight_green%28+84+%29=0\".
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Look at \"highlight_red%28+102+%29-6%2Ah-highlight_red%28+84+%29=0\".
Added fractions or integers together
It becomes \"highlight_green%28+18+%29-6%2Ah=0\".
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Look at \"highlight_red%28+18+%29-6%2Ah=0\".
Moved \"18\" to the right of expression
It becomes \"-6%2Ah%2Bhighlight_green%28+18+%29=0\".
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Look at \"highlight_red%28+-6%2Ah%2B18+%29=0\".
Solved linear equation \"highlight_red%28+-6%2Ah%2B18=0+%29\" equivalent to -6*h+18 =0
It becomes \"highlight_green%28+0+%29=0\".
Result: \"0=0\"
\n" ); document.write( "This is an equation! Solutions: h=3.

Universal Simplifier and Solver

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Done!
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