document.write( "Question 297355: .1=.159+.118log x\r
\n" ); document.write( "\n" ); document.write( "i know x=.316 but i don't know how they got that. could you explain?\r
\n" ); document.write( "\n" ); document.write( "thanks for the help!
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Algebra.Com's Answer #214139 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"0.1=0.159%2B0.118log%28%28x%29%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"0.1-0.159=0.118log%28%28x%29%29\" Subtract 0.159 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-0.059=0.118log%28%28x%29%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-0.059%2F0.118=log%28%28x%29%29\" Divide both sides by 0.118.\r
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\n" ); document.write( "\n" ); document.write( "\"-0.5=log%28%28x%29%29\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "\"x=10%5E%28-0.5%29\" Convert to exponential form\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.316227766\" Use a calculator to compute the right side.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is roughly \"x=0.316\"
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