document.write( "Question 35044: Please help me solve:
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\n" ); document.write( "sqrt*(x) = sqrt*(x - 2) - 4 \n" ); document.write( "

Algebra.Com's Answer #21405 by longjonsilver(2297) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+sqrt%28x%29+=+sqrt%28x-2%29+-+4+\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now square both sides:
\n" ); document.write( " $\"+%28sqrt%28x%29%29%5E2+=+%28sqrt%28x-2%29+-+4%29%5E2+\"$
\n" ); document.write( " $\"+x+=+%28sqrt%28x-2%29+-+4%29%28sqrt%28x-2%29+-+4%29+\"$
\n" ); document.write( " $\"+x+=+sqrt%28x-2%29sqrt%28x-2%29+-+4sqrt%28x-2%29+-+4sqrt%28x-2%29+%28-4%29%28-4%29%29+\"$
\n" ); document.write( " $\"+x+=+%28x-2%29+-+8sqrt%28x-2%29+%2B+16+\"$
\n" ); document.write( " $\"+x+=+x+-+8sqrt%28x-2%29+%2B+14+\"$
\n" ); document.write( " $\"+0+=++-+8sqrt%28x-2%29+%2B+14+\"$
\n" ); document.write( " $\"+8sqrt%28x-2%29+=+14+\"$
\n" ); document.write( " $\"+sqrt%28x-2%29+=+14%2F8+\"$
\n" ); document.write( " $\"+sqrt%28x-2%29+=+7%2F4+\"$
\n" ); document.write( " $\"+x-2+=+%287%2F4%29%5E2+\"$
\n" ); document.write( " $\"+x-2+=+49%2F16+\"$
\n" ); document.write( " $\"+x+=+2+%2B+49%2F16+\"$
\n" ); document.write( " $\"+x+=+32%2F16+%2B+49%2F16+\"$
\n" ); document.write( " $\"+x+=+81%2F16+\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now, if you put this value into the original and take the square root, remember that that gives either 9/4 OR -9/4.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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