document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=297120>Question 297120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you graph on a number line this\r<BR>\n" );
document.write( "\n" );
document.write( "|3x + 4| < 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213987 by </B><A HREF=/tutors/aboutme.mpl?userid=drparpor><B>drparpor(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drparpor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> becuase there is an absloute value u have to do this \r<BR>\n" );
document.write( "\n" );
document.write( "-7 < 3x + 4 < 7  Then solve for x by adding -4 to each side\r<BR>\n" );
document.write( "\n" );
document.write( "-11 < 3x < 3     Divide by three \r<BR>\n" );
document.write( "\n" );
document.write( "-11/3 < x < 1 \r<BR>\n" );
document.write( "\n" );
document.write( "X will be between -11/3 and 1 so the graph line will be a line going from 1 to -11/3 and the circles will be open because it's <,> not equeal to </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );