document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=297103>Question 297103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one plane flies at a ground speed 50 miles per hour faster than another. on a particular flight, the faster plane requires 3 hours and the slower one 3 hours and 30 minutes. what is the distance of the flight? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213980 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Speed of the slower plane = x miles per hour.<BR>\n" );
document.write( "Speed of the faster plane = (x+50) miles per hour.\r<BR>\n" );
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document.write( "Rate * Time = Distance.\r<BR>\n" );
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document.write( "Faster plane equation becomes:\r<BR>\n" );
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document.write( "(x+50) * 3 = D\r<BR>\n" );
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document.write( "Slower plane equation becomes:\r<BR>\n" );
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document.write( "x * 3.5 = D\r<BR>\n" );
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document.write( "Since they both equal D, then they both equal each other and we get:\r<BR>\n" );
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document.write( "(x+50) * 3 = x * 3.5\r<BR>\n" );
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document.write( "Simplify to get:\r<BR>\n" );
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document.write( "3*x + 150 = 3.5*x\r<BR>\n" );
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document.write( "Subtract 3*x from both sides of the equation to get:\r<BR>\n" );
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document.write( ".5*x = 150\r<BR>\n" );
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document.write( "Divide both sides of the equation by .5 to get:\r<BR>\n" );
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document.write( "x = 300\r<BR>\n" );
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document.write( "The slower plane is flying at 300 miles per hour.\r<BR>\n" );
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document.write( "The faster plane is traveling at 350 miles per hour.\r<BR>\n" );
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document.write( "the equation for the faster plane becomes:\r<BR>\n" );
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document.write( "350 * 3 = D = 1050 miles.\r<BR>\n" );
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document.write( "The equation for the slower plane becomes:\r<BR>\n" );
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document.write( "300 * 3.5 = D = 1050 miles.\r<BR>\n" );
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document.write( "the distance is the same in both equations as it should be.\r<BR>\n" );
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document.write( "The distance is 1050 miles.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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