document.write( "Question 297096: After riding at a steady speed for 40 miles, a bicyclist had a flat tire and walked 5 miles to a repair shop. The cyclist rate was 4 times faster than the walking rate. If the time spend on the cycling and walking was 5 hours, at what rate was the cyclist riding? \n" ); document.write( "

Algebra.Com's Answer #213971 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
After riding at a steady speed for 40 miles, a bicyclist had a flat tire and walked 5 miles to a repair shop. The cyclist rate was 4 times faster than the walking rate. If the time spend on the cycling and walking was 5 hours, at what rate was the cyclist riding?\r
\n" ); document.write( "\n" ); document.write( "let walking rate x\r
\n" ); document.write( "\n" ); document.write( "cycling rate will be 4x\r
\n" ); document.write( "\n" ); document.write( "time taken to ride 40 miles = 40/4x\r
\n" ); document.write( "\n" ); document.write( "time taken to walk 5 miles = 5/x\r
\n" ); document.write( "\n" ); document.write( "the total time taken was 5 hours \r
\n" ); document.write( "\n" ); document.write( "40/4x + 5/x = 5\r
\n" ); document.write( "\n" ); document.write( "40+20 =20x\r
\n" ); document.write( "\n" ); document.write( "60=20x\r
\n" ); document.write( "\n" ); document.write( "x=3 mph the walking rate\r
\n" ); document.write( "\n" ); document.write( "riding rate = 4x= 12 mph \n" ); document.write( "

\n" );