document.write( "Question 297097: Solve the equation
\n" ); document.write( "sqrt3r+2=2sqrt3\r
\n" ); document.write( "\n" ); document.write( "I have tried (sqrt3r+2)^2=(2sqrt3)^2
\n" ); document.write( "then got 3r+2=12
\n" ); document.write( "the i did 3r+2=12
\n" ); document.write( " -2 -2
\n" ); document.write( "and got 3r=10
\n" ); document.write( "then did 3/3 and 3/10
\n" ); document.write( "which gave me r=3.33
\n" ); document.write( "and when i check the problem it doesnt work.
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #213959 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
If the equation is $\"sqrt%283r%2B2%29=2%2Asqrt%283%29\"$ , then your answer should be $\"r=10%2F3\"$ (which in decimal form is $\"r=3.333\"$ ). For the check, I'd use the fraction answer to avoid round off error. \n" ); document.write( "

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