document.write( "Question 297022: the perimeter of a rectangle is 90m. the length is 6m longer than twice the width. what is the length and width? \n" ); document.write( "

Algebra.Com's Answer #213956 by Deina(147) $\"\"$ $\"About$

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Variables Used

p = perimeter

l = length

w = width

\n" ); document.write( "What do we know? We know that:
\n" ); document.write( "p = 90m
\n" ); document.write( "l = 2w + 6
\n" ); document.write( "and finally we know that
\n" ); document.write( "p = 2(l + w) or 2l + 2w

\n" ); document.write( "so we will substitute 2w + 6 for l in the formula:
\n" ); document.write( "p = 2(2w + 6) + 2w
\n" ); document.write( "Now we will distribute:
\n" ); document.write( "p = 4w + 12 + 2w
\n" ); document.write( "combine like terms:
\n" ); document.write( "p = 6w + 12
\n" ); document.write( "I like working on the left, so we'll flip-flop (advanced mathematical term) and replace \"p\" with 90:
\n" ); document.write( "6w + 12 = 90

\n" ); document.write( "subtract 12 from each side:
\n" ); document.write( "6w = 78
\n" ); document.write( "divide each side by 6:
\n" ); document.write( " $\"+cross%286%29w%2Fcross%286%29+=+78%2F6+=+13+\"$ so
\n" ); document.write( "w = 13
\n" ); document.write( "now remember that l = 2w + 6, and substitute 13 for 'w'
\n" ); document.write( " $\"+l+=+cross%282%2813%29%29+26+%2B+6+=+32+\"$
\n" ); document.write( "l = 32.\r
\n" ); document.write( "\n" ); document.write( "Your answers are
\n" ); document.write( "Length = 32m
\n" ); document.write( "Width = 13m & bob's your uncle!\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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