document.write( "Question 296817: 1. Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State your answer for both variables\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 45 cm. The length is 12 cm longer than the width. Find the dimensions\r
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Algebra.Com's Answer #213940 by ankor@dixie-net.com(22740)\"\" \"About 
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1. Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State your answer for both variables
\n" ); document.write( "The perimeter of a rectangle is 45 cm.
\n" ); document.write( "2L + 2W = 45
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\n" ); document.write( "The length is 12 cm longer than the width.
\n" ); document.write( "L = W + 12
\n" ); document.write( "L - W = 12
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\n" ); document.write( "Multiply the above equation by 2, and add to the 1st equation
\n" ); document.write( "2L - 2W = 24
\n" ); document.write( "2L + 2W = 45
\n" ); document.write( "---------------addition eliminates W, find L
\n" ); document.write( "4L = 69
\n" ); document.write( "L = \"69%2F4\"
\n" ); document.write( "L = 17.25 cm is the length
\n" ); document.write( "then
\n" ); document.write( "W = 17.25 - 12
\n" ); document.write( "W = 5.25 cm is the width
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\n" ); document.write( "Check solutions:
\n" ); document.write( "2(17.25) + 2(5.25) =
\n" ); document.write( "34.5 + 10.5 = 45\r
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