document.write( "Question 296950: what is 2log5x - log5 2= log5(2x+6) \n" ); document.write( "
Algebra.Com's Answer #213887 by dabanfield(803)\"\" \"About 
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what is 2log5x - log5 2= log5(2x+6)\r
\n" ); document.write( "\n" ); document.write( "2log5 x = log5 x^2 so the left side above becomes:\r
\n" ); document.write( "\n" ); document.write( "log5 x^2 - log5 2 = log5 (x^2/2)\r
\n" ); document.write( "\n" ); document.write( "We have then:\r
\n" ); document.write( "\n" ); document.write( "log5 (x^2/2) = log5 (2x+6) so\r
\n" ); document.write( "\n" ); document.write( "x^2/2 = 2x+6
\n" ); document.write( "x^2 = 2*(2x+6)
\n" ); document.write( "x^2 = 4x + 12
\n" ); document.write( "x^2 - 4x - 12 = 0
\n" ); document.write( "(x-6)*(x+2) = 0\r
\n" ); document.write( "\n" ); document.write( "x-6 = 0 or x+2 = 0
\n" ); document.write( "x = 6 or x = -2
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