document.write( "Question 296934: a kayak can travel 12 miles upstream in 6 hours. It only takes 1.5 hours for the kayak to travel the same distance downstream. Find the speed of the kayak in still water and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #213876 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A kayak can travel 12 miles upstream in 6 hours. It only takes 1.5 hours for the kayak to travel the same distance downstream. Find the speed of the kayak in still water and the speed of the current. \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "Up DATA: \n" ); document.write( "time = 6 hrs; distance = 12 miles ; rate = d/t = 2 mph \n" ); document.write( "-------------------------------------- \n" ); document.write( "Down DATA: \n" ); document.write( "time = 3/2 hrs; distance = 12 miles ; rate = d/t = 12/(3/2) = 8 mph \n" ); document.write( "-------------------------------------- \n" ); document.write( "Equations: \n" ); document.write( "Up: b - c = 2 mph \n" ); document.write( "Down: b + c = 8 mph \n" ); document.write( "------------------------------ \n" ); document.write( "Add and solve for \"b\": \n" ); document.write( "2b = 10 \n" ); document.write( "b = 5 mph (speed of the boat in still water) \n" ); document.write( "--- \n" ); document.write( "Since b+c=8, c = 3 mph (speed of the current) \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |