document.write( "Question 35200: there are 3 times as many pears as oranges. If a group of children receives 5 organges each, there will be no oranges left over. If the same group of children receives 8 pears each, there will be 21 pears left over. How many children and organges are there? \n" ); document.write( "
Algebra.Com's Answer #21387 by venugopalramana(3286)\"\" \"About 
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there are 3 times as many pears as oranges. If a group of children receives 5 organges each, there will be no oranges left over. If the same group of children receives 8 pears each, there will be 21 pears left over. How many children and organges are there?
\n" ); document.write( "LET ORANGES=X
\n" ); document.write( "PEARS ARE 3 TIMES =3X
\n" ); document.write( "LET CHILDREN=Y
\n" ); document.write( "IF WE GIVE 5 ORANGES PER CHILD WE NEED 5Y ORANGES.SO THIS =X
\n" ); document.write( "X=5Y........................I
\n" ); document.write( "IF WE GIVE 8 PEARS PER CHILD WE NEED 8Y PERARS...THERE ARE STILL 21 PEARS LEFT OUT AFTER THIS THAT IS
\n" ); document.write( "8Y+21=3X....................II
\n" ); document.write( "SUBSTITUTING FOR X FROM EQN.I..
\n" ); document.write( "8Y+21=3*5Y
\n" ); document.write( "15Y-8Y=21
\n" ); document.write( "7Y=21
\n" ); document.write( "Y=3
\n" ); document.write( "X==5Y=5*3=15..
\n" ); document.write( "SO CHILDREN =3
\n" ); document.write( "ORANGES=15
\n" ); document.write( "PEARS=3*15=45
\n" ); document.write( " \n" ); document.write( "
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