document.write( "Question 296846: Please tell me if I am doing this right, the equation is {log6 (x+3) + log6 (x+4)= 1} I end up with x=-6 and x=-1 but they cant have a negative answer?? \n" ); document.write( "
Algebra.Com's Answer #213843 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Please tell me if I am doing this right, the equation is {log6 (x+3) + log6 (x+4)= 1} I end up with x=-6 and x=-1 but they cant have a negative answer??
\n" ); document.write( "------------------
\n" ); document.write( "\"log%286%2C%28x%2B3%29%29+%2B+log%286%2C%28x%2B4%29%29+=+1\"
\n" ); document.write( "\"log%286%2C%28x%2B3%29%2A%28x%2B4%29%29+=+1\"
\n" ); document.write( "(x+3)*(x+4) = 6
\n" ); document.write( "\"x%5E2+%2B+7x+%2B+12+=+6\"
\n" ); document.write( "\"x%5E2+%2B+7x+%2B+6+=+0\"
\n" ); document.write( "(x+1)*(x+6) = 0
\n" ); document.write( "x = -6 would make it the log of a negative number, so ignore that one.
\n" ); document.write( "x = -1 works, because the arguments of the logs are both positive.
\n" ); document.write( "--> \"log%286%2C2%29+%2B+log%286%2C3%29+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" );