document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=296777>Question 296777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this Quadradic Equation by factoring\r<BR>\n" );
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document.write( "3m^=20-7m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213830 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I assume that this is 3m^2 = 20-7m  so the first thing you must do is get it into standard form of ax^2 + bx + c = 0..to do that you must first add 7m to both sides then subtract 20 from both sides and you will end up with\r<BR>\n" );
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document.write( "3m^2+7m-20 = 0  ...now you can factor..use 4 and 5 for 20:\r<BR>\n" );
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document.write( "(3m-5)(m+4) = 0   ...now you can say\r<BR>\n" );
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document.write( "3m-5=0   then 3m=5   then m=5/3   and/or<BR>\n" );
document.write( "m+4=0  then m= -4\r<BR>\n" );
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document.write( "go back and use each in the original equation...both work so the answer is both <BR>\n" );
document.write( "-4 and 5/3\r<BR>\n" );
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document.write( "Hope this helps </SPAN>\n" );
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