document.write( "Question 296786: 700 tickets for 13330, $25 for adults, $15 for students. How many of each ticket was sold. How to I get a formula for that \n" ); document.write( "

Algebra.Com's Answer #213807 by blwinbbbles(106) $\"\"$ $\"About$

You can put this solution on YOUR website!
Start with your equations...let x be adult and y be student\r
\n" ); document.write( "\n" ); document.write( "If there were 700 tickets sold then equation 1 is x+y=700
\n" ); document.write( "and there was $13330 sold so equation 2 is 25x+15y=13330\r
\n" ); document.write( "\n" ); document.write( "1) x+y=700 you can rearrange this..subtract y from both sides so
\n" ); document.write( "that x=700-y
\n" ); document.write( "2) 25x+15y=13330\r
\n" ); document.write( "\n" ); document.write( "since we know that x=700-y we can sub that into equation 2\r
\n" ); document.write( "\n" ); document.write( "25(700-y)+15y = 13330
\n" ); document.write( "17500-25y+15y = 13330
\n" ); document.write( "17500-10y=13330 subtract 17500 from both sides
\n" ); document.write( "-10y= -4170 divide both sides by -10
\n" ); document.write( "y=417 so now you can go back and use y=417 in equation 1.\r
\n" ); document.write( "\n" ); document.write( "x+417=700 subtract 417 from both sides
\n" ); document.write( "x=283
\n" ); document.write( "so they sold 283 adult tickets and 417 student tickets
\n" ); document.write( "Hope this helps \n" ); document.write( "

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