document.write( "Question 296682: The force exerted on the soles of the feet for a typical basketball jump shot is directly proportional to the shooter's weight. If a 150 lb player exerts a force of 2000 lbs, what force is exerted by a 6ft 8in. 280 lb player? \n" ); document.write( "
Algebra.Com's Answer #213741 by jim_thompson5910(35256)\"\" \"About 
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Let F = force exerted and w = weight\r
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\n" ); document.write( "\n" ); document.write( "So \"The force exerted on the soles of the feet for a typical basketball jump shot is directly proportional to the shooter's weight\" means that \"F=kw\" for some constant 'k'\r
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\n" ); document.write( "\n" ); document.write( "Because we're given that \"a 150 lb player exerts a force of 2000 lbs\", we know that \"F=2000\" and \"w=150\". Plug these into the equation above to get \"2000=k%28150%29\". From here, divide both sides by 150 to get \"k=2000%2F150=40%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So the equation is \"F=%2840%2F3%29w\". Now just plug in \"w=280\" to find 'F' for a 280 lb player. \r
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\n" ); document.write( "\n" ); document.write( "Note: the given info on the height of the player has nothing to do with the problem. That's just there to throw you off.
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