document.write( "Question 296645: Any help on this problem would be great\r
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\n" ); document.write( "\n" ); document.write( "2(y – 1)^2 = 4(y + 1)^2\r
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Algebra.Com's Answer #213739 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%28y-1%29%5E2+=+4%28y+%2B+1%29%5E2+\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28y%5E2-2y+%2B+1%29+=+4%28y%5E2%2B2y+%2B+1%29+\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"2y%5E2-4y+%2B+2+=+4y%5E2%2B8y+%2B+4+\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+4y%5E2%2B8y+%2B+4-2y%5E2%2B4y-2+\" Get everything to one side.\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+2y%5E2%2B12y+%2B+2+\" Combine like terms.\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for y:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ay%5E2%2Bby%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"2%2Ay%5E2%2B12%2Ay%2B2=0\" ( notice \"a=2\", \"b=12\", and \"c=2\")
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\n" ); document.write( " \"y+=+%28-12+%2B-+sqrt%28+%2812%29%5E2-4%2A2%2A2+%29%29%2F%282%2A2%29\" Plug in a=2, b=12, and c=2
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\n" ); document.write( " \"y+=+%28-12+%2B-+sqrt%28+144-4%2A2%2A2+%29%29%2F%282%2A2%29\" Square 12 to get 144
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\n" ); document.write( " \"y+=+%28-12+%2B-+sqrt%28+144%2B-16+%29%29%2F%282%2A2%29\" Multiply \"-4%2A2%2A2\" to get \"-16\"
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\n" ); document.write( " \"y+=+%28-12+%2B-+sqrt%28+128+%29%29%2F%282%2A2%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"y+=+%28-12+%2B-+8%2Asqrt%282%29%29%2F%282%2A2%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"y+=+%28-12+%2B-+8%2Asqrt%282%29%29%2F4\" Multiply 2 and 2 to get 4
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"y+=+%28-12+%2B+8%2Asqrt%282%29%29%2F4\" or \"y+=+%28-12+-+8%2Asqrt%282%29%29%2F4\"
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\n" ); document.write( " Now break up the fraction
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\n" ); document.write( " \"y=-12%2F4%2B8%2Asqrt%282%29%2F4\" or \"y=-12%2F4-8%2Asqrt%282%29%2F4\"
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\n" ); document.write( " Simplify
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\n" ); document.write( " \"y=-3%2B2%2Asqrt%282%29\" or \"y=-3-2%2Asqrt%282%29\"
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\n" ); document.write( " So the solutions are:
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\n" ); document.write( " \"y=-3%2B2%2Asqrt%282%29\" or \"y=-3-2%2Asqrt%282%29\"
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