document.write( "Question 296658: If x is an integer greater than 1 and if y = x + (1/x), which of the following must be true ?\r
\n" ); document.write( "\n" ); document.write( "I y ≠ x
\n" ); document.write( "II y is an integer
\n" ); document.write( "III xy > x^2\r
\n" ); document.write( "\n" ); document.write( "(A) I only
\n" ); document.write( "(B) III only
\n" ); document.write( "(C) I and II only
\n" ); document.write( "(D) I and III only
\n" ); document.write( "(E) I , II ,and III only
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #213735 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, we need to see if statement I is true or not. Assume that \"y=x\", if this is the case, then \"x%2B1%2Fx=x\". Subtract 'x' from both sides to get \"1%2Fx=0\". Since this equation is NEVER true for any 'x' values (let alone positive 'x' values), we can say that \"y=x\" is false where \"y=x%2B1%2Fx\". So this means that \"y%3C%3Ex\" and that statement I is true.\r
\n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "If \"x%3E1\", then \"1%2Fx\" is NOT an integer. So this consequently means that \"x%2B1%2Fx\" is also NOT an integer. So statement II is false meaning that choices C and E can be ignored.\r
\n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Finally, because 'x' is an integer and 'x' is positive, we also know that \"x%3Cx%2B1%2Fx\" or that \"x%3Cy\" (do a simple substitution here). Multiply both sides by 'x' to get \"x%5E2%3Cxy\" (note: the sign doesn't flip because 'x' is positive).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So we've shown that if 'x' is an integer and 'x' is positive, then \"x%5E2%3Cxy\" where \"y=x%2B1%2Fx\". So statement III is true.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So because statements I and III are both true, we can say that the answer is choice D.
\n" ); document.write( "
\n" );