document.write( "Question 296668: On a 135-mile bicycle trip, John averaged 5 miles per hour faster for the first 60 miles than he did for the last 75 miles. The entire trip took eight hours. Find his rate for the first 60 miles. \n" ); document.write( "
Algebra.Com's Answer #213731 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "T=D/R
\n" ); document.write( "8=60/(R+5)+75/R
\n" ); document.write( "8=[(60R+75(R+5)]/R(R+5)
\n" ); document.write( "8=[60R+75R+375]/R^2+5R
\n" ); document.write( "8(R^2+5R)=135R+375
\n" ); document.write( "8R^2+40R-135R-375=0
\n" ); document.write( "8R^2-95R-375=0
\n" ); document.write( "(x-15)(8x+25)=0
\n" ); document.write( "x-15=0
\n" ); document.write( "x=15 mph is the speed for the 75 mile leg.
\n" ); document.write( "15+5=20mph is the speed for the 60 mile leg.
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