document.write( "Question 296657: solve b^4 + 2b^2 - 24 = 0\r
\n" ); document.write( "\n" ); document.write( "a) -2, -sqrt6, sqrt6, 2
\n" ); document.write( "b) -sqrt6, 2, 2i, i sqrt6
\n" ); document.write( "c) -2, 2, -i sqrt6, i sqrt6
\n" ); document.write( "d) -2i, 2i - sqrt6, sqrt6
\n" ); document.write( "

Algebra.Com's Answer #213724 by richwmiller(17219)\"\" \"About 
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\n" ); document.write( "Since all complex roots come in plus minus pairs, answer b is out
\n" ); document.write( "To solve the equation, substitute u for b^2
\n" ); document.write( "b^4 + 2b^2 - 24 = 0
\n" ); document.write( "u^2+2u-24=0
\n" ); document.write( "(u-4)*(u+6)=0
\n" ); document.write( "now plug b^2 back in for u\r
\n" ); document.write( "\n" ); document.write( "(b^2-4)*(b^+6)=0
\n" ); document.write( "(b-2)*(b+2)*(b^2+6)=0
\n" ); document.write( "solve for b
\n" ); document.write( "so b = +-2
\n" ); document.write( "answer d is out
\n" ); document.write( "b^2=-6
\n" ); document.write( "so answer a is out
\n" ); document.write( "so it must be answer c
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