document.write( "Question 296571: The perimeter of a rectangle is six times the width. If the length were increased by 4 inches and the width were increased by 7 inches, then the perimeter would be 160 inches. What are the length and the width? \n" ); document.write( "
Algebra.Com's Answer #213676 by mananth(16946)\"\" \"About 
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let the width be x\r
\n" ); document.write( "\n" ); document.write( "the perimeter = 6x\r
\n" ); document.write( "\n" ); document.write( "sum of the lengths = 6x-2x = 4x\r
\n" ); document.write( "\n" ); document.write( "each lengh of rectangle = 2x\r
\n" ); document.write( "\n" ); document.write( "2*(2x+4)+2*(x+7)=160\r
\n" ); document.write( "\n" ); document.write( "4x+8 + 2x+14 =160\r
\n" ); document.write( "\n" ); document.write( "^x+22 =160\r
\n" ); document.write( "\n" ); document.write( "6x=138\r
\n" ); document.write( "\n" ); document.write( "x= 138/3\r
\n" ); document.write( "\n" ); document.write( "x= 23 the width\r
\n" ); document.write( "\n" ); document.write( "length = 2x = 46\r
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