document.write( "Question 296585: A father is four times his son's age.And in 30yrs the son will be half as old as his father.How old are the father and son each now? \n" ); document.write( "
Algebra.Com's Answer #213675 by mananth(16946)\"\" \"About 
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let son's age be x\r
\n" ); document.write( "\n" ); document.write( "the father's age = 4x\r
\n" ); document.write( "\n" ); document.write( "after 30 years \r
\n" ); document.write( "\n" ); document.write( "son's age = x+30\r
\n" ); document.write( "\n" ); document.write( "father's age = 4x+30\r
\n" ); document.write( "\n" ); document.write( "1/2* 4x+30 = x+30\r
\n" ); document.write( "\n" ); document.write( "4x+30 = 2*(x+30)\r
\n" ); document.write( "\n" ); document.write( "4x+30= 2x+60\r
\n" ); document.write( "\n" ); document.write( "4x-2x= 60-30\r
\n" ); document.write( "\n" ); document.write( "2x=30\r
\n" ); document.write( "\n" ); document.write( "x=15 son's age\r
\n" ); document.write( "\n" ); document.write( "father's age = 4x= 4*15 = 60 years\r
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