document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=296495>Question 296495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound. How many pounds of the cheaper kind should they use in the mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213617 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound. How many pounds of the cheaper kind should they use in the mix?\r<BR>\n" );
document.write( "\n" );
document.write( "let x pounds of cheaper feed be required\r<BR>\n" );
document.write( "\n" );
document.write( "the other one required will be 54-x\r<BR>\n" );
document.write( "\n" );
document.write( "0.24*(x)+0.42(54-x)=0.28 * 54\r<BR>\n" );
document.write( "\n" );
document.write( "0.24x +22.68 -0.42x =15.12\r<BR>\n" );
document.write( "\n" );
document.write( "0.24x-0.42x=15.12-22.68\r<BR>\n" );
document.write( "\n" );
document.write( "0.18x= 7.56\r<BR>\n" );
document.write( "\n" );
document.write( "x=7.56 / 0.18\r<BR>\n" );
document.write( "\n" );
document.write( "x=42 lbs-  the cheaper variety\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );